What is expand (11x+12)/((2x+3)(x+2)(x-3)) ?

The solution to expand (11x+12)/((2x+3)(x+2)(x-3)) is (11x+12)/(2x^3+x^2-15x-18)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (11x+12)/((2x+3)(x+2)(x-3))

expand

\frac{11 x + 12}{( 2 x + 3 ) ( x + 2 ) ( x - 3 )}

\frac{11 x + 12}{2 x ^{3} + x ^{2} - 15 x - 18}

Solution steps

\frac{11 x + 12}{( 2 x + 3 ) ( x + 2 ) ( x - 3 )}

Expand

(2 x + 3) (x + 2) (x - 3) : 2 x^{3} + x^{2} - 15 x - 18

= \frac{11 x + 12}{2 x ^{3} + x ^{2} - 15 x - 18}

(3 x - x^{3}) (- 7 x + π) + e^{9 x}

(t^{2} + (t^{2})^{2}, 4 t \cdot t^{2}) \cdot (1, 2 t)

\frac{( x + 1 ) ^{2}}{x ^{2} + 2 x - 3}

- (1 + 2) x

(2 - \frac{1}{2 ^{n}}) (3 + \frac{1}{2 ^{n}})

What is expand (11x+12)/((2x+3)(x+2)(x-3)) ?
The solution to expand (11x+12)/((2x+3)(x+2)(x-3)) is (11x+12)/(2x^3+x^2-15x-18)