What is (a^2b+8/3)(a^2b-8/3) ?

The solution to (a^2b+8/3)(a^2b-8/3) is ((3a^2b+8)(3a^2b-8))/9

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simplify (a^2b+8/3)(a^2b-8/3)

simplify

(a^{2} b + \frac{8}{3}) (a^{2} b - \frac{8}{3})

\frac{( 3 a ^{2} b + 8 ) ( 3 a ^{2} b - 8 )}{9}

Solution steps

(a^{2} b + \frac{8}{3}) (a^{2} b - \frac{8}{3})

Simplify

a^{2} b + \frac{8}{3} : \frac{3 a ^{2} b + 8}{3}

= \frac{3 a ^{2} b + 8}{3} (a^{2} b - \frac{8}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 a ^{2} b + 8 ) ( a ^{2} b - \frac{8}{3} )}{3}

Simplify

(3 a^{2} b + 8) (a^{2} b - \frac{8}{3}) : \frac{( 3 a ^{2} b + 8 ) ( a ^{2} b \cdot 3 - 8 )}{3}

= \frac{\frac{( 3 a ^{2} b + 8 ) ( a ^{2} b \cdot 3 - 8 )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 a ^{2} b + 8 ) ( a ^{2} b \cdot 3 - 8 )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 3 a ^{2} b + 8 ) ( a ^{2} b \cdot 3 - 8 )}{9}

= \frac{( 3 a ^{2} b + 8 ) ( 3 a ^{2} b - 8 )}{9}

\frac{x + 1}{x ( x + 5 )}

5 \cdot (3 + 3)

(3 t (x) - 5) x^{^{'}}

(sin (t) - cos (2 t))^{2}

(2, 3 i) (2, - 3 i)

What is (a^2b+8/3)(a^2b-8/3) ?
The solution to (a^2b+8/3)(a^2b-8/3) is ((3a^2b+8)(3a^2b-8))/9