What is expand (2sin(θ)-1)^2 ?

The solution to expand (2sin(θ)-1)^2 is 4sin^2(θ)-4sin(θ)+1

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expand (2sin(θ)-1)^2

expand

(2 sin (θ) - 1)^{2}

4 sin^{2} (θ) - 4 sin (θ) + 1

Solution steps

(2 sin (θ) - 1)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(2 sin (θ) - 1)^{2} = (2 sin (θ))^{2} - 2 \cdot 2 sin (θ) \cdot 1 + 1^{2}

= (2 sin (θ))^{2} - 2 \cdot 2 sin (θ) \cdot 1 + 1^{2}

Simplify

(2 sin (θ))^{2} - 2 \cdot 2 sin (θ) \cdot 1 + 1^{2} : 4 sin^{2} (θ) - 4 sin (θ) + 1

= 4 sin^{2} (θ) - 4 sin (θ) + 1

(7 t^{2} + \frac{1}{4}) (7 t^{2} - \frac{1}{4})

(\frac{1 - cos ( 2 x )}{2})^{3}

\frac{( a ^{2} b ^{3} c - 4 ) 2}{( ab c ) 3}

\frac{6 x}{( x ^{2} + 2 ) ^{2}}

\frac{( sec ( x ) ) ^{2} β - sin ( β ) tan ( β )}{cos ( x )}

What is expand (2sin(θ)-1)^2 ?
The solution to expand (2sin(θ)-1)^2 is 4sin^2(θ)-4sin(θ)+1