What is expand e^{2x}*(-log_{n}(2x+1)-2x) ?

The solution to expand e^{2x}*(-log_{n}(2x+1)-2x) is -e^{2x}log_{n}(2x+1)-2e^{2x}x

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expand e^{2x}*(-log_{n}(2x+1)-2x)

expand

e^{2 x} \cdot (- lo g_{n} (2 x + 1) - 2 x)

- e^{2 x} lo g_{n} (2 x + 1) - 2 e^{2 x} x

Solution steps

e^{2 x} (- lo g_{n} (2 x + 1) - 2 x)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 x}, b = - lo g_{n} (2 x + 1), c = 2 x

= e^{2 x} (- lo g_{n} (2 x + 1)) - e^{2 x} \cdot 2 x

Apply minus-plus rules

+ (- a) = - a

= - e^{2 x} lo g_{n} (2 x + 1) - 2 e^{2 x} x

6 (x + 7)

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What is expand e^{2x}*(-log_{n}(2x+1)-2x) ?
The solution to expand e^{2x}*(-log_{n}(2x+1)-2x) is -e^{2x}log_{n}(2x+1)-2e^{2x}x