What is expand (2pi(216-35sqrt(35)))/3 ?

The solution to expand (2pi(216-35sqrt(35)))/3 is 144pi-(70sqrt(35)pi)/3

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expand (2pi(216-35sqrt(35)))/3

expand

\frac{2 π ( 216 - 35 35 )}{3}

144 π - \frac{70 35 π}{3}

Decimal Notation

18.71804 \dots

Solution steps

\frac{2 π ( 216 - 35 35 )}{3}

Expand

2 π (216 - 3535) : 432 π - 7035 π

= \frac{432 π - 70 35 π}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{432 π - 70 35 π}{3} = \frac{432 π}{3} - \frac{70 35 π}{3}

= \frac{432 π}{3} - \frac{70 35 π}{3}

Divide the numbers:

\frac{432}{3} = 144

= 144 π - \frac{70 35 π}{3}

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(a 2 + b 3)^{(4)}

(2 x - 1)^{3} cosh (4 x)

What is expand (2pi(216-35sqrt(35)))/3 ?
The solution to expand (2pi(216-35sqrt(35)))/3 is 144pi-(70sqrt(35)pi)/3