What is expand (3x^2(x+3)-x(x^3+2))/((x+3)^2) ?

The solution to expand (3x^2(x+3)-x(x^3+2))/((x+3)^2) is (3x^3+9x^2-x^4-2x)/(x^2+6x+9)

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expand (3x^2(x+3)-x(x^3+2))/((x+3)^2)

expand

\frac{3 x ^{2} ( x + 3 ) - x ( x ^{3} + 2 )}{( x + 3 ) ^{2}}

\frac{3 x ^{3} + 9 x ^{2} - x ^{4} - 2 x}{x ^{2} + 6 x + 9}

Solution steps

\frac{3 x ^{2} ( x + 3 ) - x ( x ^{3} + 2 )}{( x + 3 ) ^{2}}

(x + 3)^{2} = x^{2} + 6 x + 9

= \frac{3 x ^{2} ( x + 3 ) - x ( x ^{3} + 2 )}{x ^{2} + 6 x + 9}

Expand

3 x^{2} (x + 3) - x (x^{3} + 2) : 3 x^{3} + 9 x^{2} - x^{4} - 2 x

= \frac{3 x ^{3} + 9 x ^{2} - x ^{4} - 2 x}{x ^{2} + 6 x + 9}

D x [(1 + x^{2}) (1 + 2 x^{2})]

x (800 - \frac{x}{6})

\frac{( 0.2 + x ) ( 0.2 + 2 x ) ^{2}}{( 0.2 - 2 x ) ^{2}}

- (\frac{- s ^{2} + 1}{( s ^{2} + 1 ) ^{2}})

\frac{( ln ( x ) ) ^{2} - 2}{x}

What is expand (3x^2(x+3)-x(x^3+2))/((x+3)^2) ?
The solution to expand (3x^2(x+3)-x(x^3+2))/((x+3)^2) is (3x^3+9x^2-x^4-2x)/(x^2+6x+9)