What is expand-4/((e^x-e^{-x))^2} ?

The solution to expand-4/((e^x-e^{-x))^2} is -4/(e^{2x)-2+e^{-2x}}

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expand-4/((e^x-e^{-x))^2}

expand

- \frac{4}{( e ^{x} - e ^{- x} ) ^{2}}

- \frac{4}{e ^{2 x} - 2 + e ^{- 2 x}}

Solution steps

- \frac{4}{( e ^{x} - e ^{- x} ) ^{2}}

(e^{x} - e^{- x})^{2} = e^{2 x} - 2 + e^{- 2 x}

= - \frac{4}{e ^{2 x} + e ^{- 2 x} - 2}

(- 8 i + (- 5), 2 j) \cdot (9, 7 i + (- 0), 7 j)

- \frac{2 ( 4 + 79 )}{3}

\frac{n ( n - 1 ) ^{2}}{2}

\frac{π ( 8 + 2 ln ( 5 ) )}{2}

(x + e)^{3}

What is expand-4/((e^x-e^{-x))^2} ?
The solution to expand-4/((e^x-e^{-x))^2} is -4/(e^{2x)-2+e^{-2x}}