What is expand a^2b^2-c^2d^2(sin(2α)+1) ?

The solution to expand a^2b^2-c^2d^2(sin(2α)+1) is a^2b^2-c^2d^2sin(2α)-c^2d^2

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expand a^2b^2-c^2d^2(sin(2α)+1)

expand

a^{2} b^{2} - c^{2} d^{2} (sin (2 α) + 1)

a^{2} b^{2} - c^{2} d^{2} sin (2 α) - c^{2} d^{2}

Solution steps

a^{2} b^{2} - c^{2} d^{2} (sin (2 α) + 1)

Apply the distributive law:

a (b + c) = ab + a c

- c^{2} d^{2} (sin (2 α) + 1) = - c^{2} d^{2} sin (2 α) - c^{2} d^{2} \cdot 1

= a^{2} b^{2} - c^{2} d^{2} sin (2 α) - c^{2} d^{2} \cdot 1

Apply rule:

a \cdot 1 = a

- c^{2} d^{2} \cdot 1 = - c^{2} d^{2}

= a^{2} b^{2} - c^{2} d^{2} sin (2 α) - c^{2} d^{2}

(1 - L) \cdot (1 - t) \cdot w

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\frac{x}{( x + 1 ) ( x - 1 )}

e^{\frac{1}{3} (\frac{s ^{2}}{2} - 9 l n ∣ s ∣)}

2.8 tan (0.7 x - 1.8) - 2 (- 2, - 0.53)

What is expand a^2b^2-c^2d^2(sin(2α)+1) ?
The solution to expand a^2b^2-c^2d^2(sin(2α)+1) is a^2b^2-c^2d^2sin(2α)-c^2d^2