What is 1/((1-x)(kx)^{0.5)} ?

The solution to 1/((1-x)(kx)^{0.5)} is 1/((1-x)k^{0.5)x^{0.5}}

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simplify 1/((1-x)(kx)^{0.5)}

simplify

\frac{1}{( 1 - x ) ( k x ) ^{0.5}}

\frac{1}{( 1 - x ) k ^{0.5} x ^{0.5}}

Solution steps

\frac{1}{( 1 - x ) ( k x ) ^{0.5}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(k x)^{0.5} = k^{0.5} x^{0.5}

= \frac{1}{( 1 - x ) k ^{0.5} x ^{0.5}}

- \frac{2 x + 1}{( 1 + x + x ^{2} ) ^{2}}

5 (3 + 2)

(x - 1) (x + 2 i) (x - 2 i)

(\frac{1}{12}) (t) (L + \frac{t}{2} + \frac{R}{2})^{3}

\frac{110 ( ln ( x ) - 2 )}{x}

What is 1/((1-x)(kx)^{0.5)} ?
The solution to 1/((1-x)(kx)^{0.5)} is 1/((1-x)k^{0.5)x^{0.5}}