What is expand (e^{x/m}-e^{-x/m})^2 ?

The solution to expand (e^{x/m}-e^{-x/m})^2 is e^{(2x)/m}-2+e^{-(2x)/m}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{x/m}-e^{-x/m})^2

expand

(e^{\frac{x}{m}} - e^{- \frac{x}{m}})^{2}

e^{\frac{2 x}{m}} - 2 + e^{- \frac{2 x}{m}}

Solution steps

(e^{\frac{x}{m}} - e^{- \frac{x}{m}})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = e^{\frac{x}{m}}, b = e^{- \frac{x}{m}}

= (e^{\frac{x}{m}})^{2} - 2 e^{\frac{x}{m}} e^{- \frac{x}{m}} + (e^{- \frac{x}{m}})^{2}

Simplify

(e^{\frac{x}{m}})^{2} - 2 e^{\frac{x}{m}} e^{- \frac{x}{m}} + (e^{- \frac{x}{m}})^{2} : e^{\frac{2 x}{m}} - 2 + e^{- \frac{2 x}{m}}

= e^{\frac{2 x}{m}} - 2 + e^{- \frac{2 x}{m}}

cos^{2} (θ) (1 + tan (θ))

3 l e f t (X - 5)^{7}

\frac{( x ^{2} + 1 ) ^{4}}{8}

(x + 6 - 3) (x + 6 + 3)

(\frac{4}{x} - \frac{1}{x ^{3}})^{2}

What is expand (e^{x/m}-e^{-x/m})^2 ?
The solution to expand (e^{x/m}-e^{-x/m})^2 is e^{(2x)/m}-2+e^{-(2x)/m}