What is 1/2 (-1/7 cos(7x)-1/5 cos(5x)) ?

The solution to 1/2 (-1/7 cos(7x)-1/5 cos(5x)) is (-1/7 cos(7x)-1/5 cos(5x))/2

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simplify 1/2 (-1/7 cos(7x)-1/5 cos(5x))

simplify

\frac{1}{2} (- \frac{1}{7} cos (7 x) - \frac{1}{5} cos (5 x))

\frac{- \frac{1}{7} cos ( 7 x ) - \frac{1}{5} cos ( 5 x )}{2}

Solution steps

\frac{1}{2} (- \frac{1}{7} cos (7 x) - \frac{1}{5} cos (5 x))

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( - \frac{1}{7} cos ( 7 x ) - \frac{1}{5} cos ( 5 x ) )}{2}

Apply rule:

1 \cdot a = a

1 \cdot (- \frac{1}{7} cos (7 x) - \frac{1}{5} cos (5 x)) = (- \frac{1}{7} cos (7 x) - \frac{1}{5} cos (5 x))

= \frac{- \frac{1}{7} cos ( 7 x ) - \frac{1}{5} cos ( 5 x )}{2}

6 (5 + 9)

5 cos (0.5 (θ - π))

\frac{( - 3 x ^{2} y + 1 ) ^{3}}{27 x ^{8}}

\frac{1}{( s ^{2} + 1 ) ( s - 3 ) ( s - 6 )}

(2 + - 9)^{3}

What is 1/2 (-1/7 cos(7x)-1/5 cos(5x)) ?
The solution to 1/2 (-1/7 cos(7x)-1/5 cos(5x)) is (-1/7 cos(7x)-1/5 cos(5x))/2