What is expand ((x-3)(x+3))/((x-4)(x+4)) ?

The solution to expand ((x-3)(x+3))/((x-4)(x+4)) is (x^2-9)/(x^2-16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x-3)(x+3))/((x-4)(x+4))

expand

\frac{( x - 3 ) ( x + 3 )}{( x - 4 ) ( x + 4 )}

\frac{x ^{2} - 9}{x ^{2} - 16}

Solution steps

\frac{( x - 3 ) ( x + 3 )}{( x - 4 ) ( x + 4 )}

Expand

(x - 4) (x + 4) : x^{2} - 16

= \frac{( x - 3 ) ( x + 3 )}{x ^{2} - 16}

Expand

(x - 3) (x + 3) : x^{2} - 9

= \frac{x ^{2} - 9}{x ^{2} - 16}

(\frac{1}{3 x} - 2 x^{2})^{6}

- \frac{28735}{( x - 42.8 ) ^{2}} + \frac{0.0000072}{x ^{3}}

f (2, - 1)

\frac{2 ( x ^{4} - 16 )}{x ^{3}}

(4 x^{2} + 5) y^{''} (x) - 6 x y

What is expand ((x-3)(x+3))/((x-4)(x+4)) ?
The solution to expand ((x-3)(x+3))/((x-4)(x+4)) is (x^2-9)/(x^2-16)