What is expand ((8-x)^3)/3 ?

The solution to expand ((8-x)^3)/3 is -(x^3)/3+8x^2-64x+512/3

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expand ((8-x)^3)/3

expand

\frac{( 8 - x ) ^{3}}{3}

- \frac{x ^{3}}{3} + 8 x^{2} - 64 x + \frac{512}{3}

Solution steps

\frac{( 8 - x ) ^{3}}{3}

(8 - x)^{3} = 512 - 192 x + 24 x^{2} - x^{3}

= \frac{512 - 192 x + 24 x ^{2} - x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{512 - 192 x + 24 x ^{2} - x ^{3}}{3} = \frac{512}{3} - \frac{192 x}{3} + \frac{24 x ^{2}}{3} - \frac{x ^{3}}{3}

= \frac{512}{3} - \frac{192 x}{3} + \frac{24 x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{192}{3} = 64

= \frac{512}{3} - 64 x + \frac{24 x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{24}{3} = 8

= \frac{512}{3} - 64 x + 8 x^{2} - \frac{x ^{3}}{3}

Rewrite in standard form

= - \frac{x ^{3}}{3} + 8 x^{2} - 64 x + \frac{512}{3}

\frac{( 2 x ^{2} + 7 x + 23 )}{( x + 3 ) ( x ^{2} + 2 x - 3 )}

- \frac{x}{( x - 2 ) ^{3}}

2 (1 + sin^{2} (x)) sin (2 x)

\frac{( a + b )}{2 \cdot ( 2 + ab )}

C (5, - 2)

What is expand ((8-x)^3)/3 ?
The solution to expand ((8-x)^3)/3 is -(x^3)/3+8x^2-64x+512/3