What is expand (x^2+5)e^{9x+4} ?

The solution to expand (x^2+5)e^{9x+4} is e^{9x+4}x^2+5e^{9x+4}

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expand (x^2+5)e^{9x+4}

expand

(x^{2} + 5) e^{9 x + 4}

e^{9 x + 4} x^{2} + 5 e^{9 x + 4}

Solution steps

(x^{2} + 5) e^{9 x + 4}

= e^{9 x + 4} (x^{2} + 5)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{9 x + 4}, b = x^{2}, c = 5

= e^{9 x + 4} x^{2} + e^{9 x + 4} \cdot 5

= e^{9 x + 4} x^{2} + 5 e^{9 x + 4}

ln (7) (x + 3) + ln (7) (x - 2 = ln (7) (2 x + 14))

\frac{4 ( x - 3 )}{5}

30 (5 - 15)

\frac{7 x \cdot ln ( x ) - 7 x + 7}{ln ( x ) ( x - 1 )}

(e^{2 x} - 2 e^{x} + 1) (e^{4 x} + 2 e^{2 x} + 1)

What is expand (x^2+5)e^{9x+4} ?
The solution to expand (x^2+5)e^{9x+4} is e^{9x+4}x^2+5e^{9x+4}