What is expand (2sin(2t))(1+2sin^2(t)) ?

The solution to expand (2sin(2t))(1+2sin^2(t)) is 2sin(2t)+4sin^2(t)sin(2t)

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expand (2sin(2t))(1+2sin^2(t))

expand

(2 sin (2 t)) (1 + 2 sin^{2} (t))

2 sin (2 t) + 4 sin^{2} (t) sin (2 t)

Solution steps

(2 sin (2 t)) (1 + 2 sin^{2} (t))

Apply the distributive law:

a (b + c) = ab + a c

(2 sin (2 t)) (1 + 2 sin^{2} (t)) = 2 sin (2 t) \cdot 1 + 2 sin (2 t) \cdot 2 sin^{2} (t)

= 2 sin (2 t) \cdot 1 + 2 sin (2 t) \cdot 2 sin^{2} (t)

Simplify

2 sin (2 t) \cdot 1 + 2 sin (2 t) \cdot 2 sin^{2} (t) : 2 sin (2 t) + 4 sin^{2} (t) sin (2 t)

= 2 sin (2 t) + 4 sin^{2} (t) sin (2 t)

\frac{1}{s ^{2} ( s - 9 )}

\frac{( 5 x - 1 ) ( x + 1 )}{( 3 x - 1 ) ( x + 2 )}

x (x + 3) (x - 2) (x + 2)

7.03 \times 10 - 4

(x^{2} + 1) (- x sin (x) + 2 cos (x))

What is expand (2sin(2t))(1+2sin^2(t)) ?
The solution to expand (2sin(2t))(1+2sin^2(t)) is 2sin(2t)+4sin^2(t)sin(2t)