What is expand (3(4x^2+2-5x))/4 ?

The solution to expand (3(4x^2+2-5x))/4 is 3x^2-(15x)/4+3/2

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expand (3(4x^2+2-5x))/4

expand

\frac{3 ( 4 x ^{2} + 2 - 5 x )}{4}

3 x^{2} - \frac{15 x}{4} + \frac{3}{2}

Solution steps

\frac{3 ( 4 x ^{2} + 2 - 5 x )}{4}

Expand

3 (4 x^{2} + 2 - 5 x) : 12 x^{2} + 6 - 15 x

= \frac{12 x ^{2} + 6 - 15 x}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 x ^{2} + 6 - 15 x}{4} = \frac{12 x ^{2}}{4} + \frac{6}{4} - \frac{15 x}{4}

= \frac{12 x ^{2}}{4} + \frac{6}{4} - \frac{15 x}{4}

Divide the numbers:

\frac{12}{4} = 3

= 3 x^{2} + \frac{6}{4} - \frac{15 x}{4}

Cancel

\frac{6}{4} : \frac{3}{2}

= 3 x^{2} + \frac{3}{2} - \frac{15 x}{4}

Rewrite in standard form

= 3 x^{2} - \frac{15 x}{4} + \frac{3}{2}

(x^{3} + \frac{10}{x ^{2}})^{10}

18 (3 sin (x) - 4 sin^{3} (x))

(x - 5 - 2) (x - 5 + 2)

(x - 3) (x + 2) (x - 2) (x - 2) (x + 2)

\frac{( a - 2 ) ( a ^{4} + 2 a ^{3} - 2 a ^{2} - 4 a + 4 )}{( a ^{2} - 2 ) ^{2}}

What is expand (3(4x^2+2-5x))/4 ?
The solution to expand (3(4x^2+2-5x))/4 is 3x^2-(15x)/4+3/2