What is expand (1+3sin(2x))cos(2x) ?

The solution to expand (1+3sin(2x))cos(2x) is cos(2x)+3cos(2x)sin(2x)

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expand (1+3sin(2x))cos(2x)

expand

(1 + 3 sin (2 x)) cos (2 x)

cos (2 x) + 3 cos (2 x) sin (2 x)

Solution steps

(1 + 3 sin (2 x)) cos (2 x)

= cos (2 x) (1 + 3 sin (2 x))

Apply the distributive law:

a (b + c) = ab + a c

cos (2 x) (1 + 3 sin (2 x)) = cos (2 x) \cdot 1 + cos (2 x) \cdot 3 sin (2 x)

= cos (2 x) \cdot 1 + cos (2 x) \cdot 3 sin (2 x)

Simplify

cos (2 x) \cdot 1 + cos (2 x) \cdot 3 sin (2 x) : cos (2 x) + 3 cos (2 x) sin (2 x)

= cos (2 x) + 3 cos (2 x) sin (2 x)

\frac{5 s ^{2} - 2 s - 3}{( s ^{2} + 1 ) ( s ^{2} - 2 s + 5 )}

(1 + i) \cdot e^{\frac{i}{1 + i}}

(2 x - 1) (x)

(2 d + 5 e) (4 d^{2} - 10 d e + 25 e^{2})

\frac{( x - 7 ) ( x - 2 )}{( x + 2 ) ( x - 1 ) ^{2}}

What is expand (1+3sin(2x))cos(2x) ?
The solution to expand (1+3sin(2x))cos(2x) is cos(2x)+3cos(2x)sin(2x)