What is (1-((x^2))/2)*(x-((x^3))/6) ?

The solution to (1-((x^2))/2)*(x-((x^3))/6) is ((2-x^2)(6x-x^3))/(12)

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simplify (1-((x^2))/2)*(x-((x^3))/6)

simplify

(1 - \frac{( x ^{2} )}{2}) \cdot (x - \frac{( x ^{3} )}{6})

\frac{( 2 - x ^{2} ) ( 6 x - x ^{3} )}{12}

Solution steps

(1 - \frac{x ^{2}}{2}) (x - \frac{x ^{3}}{6})

Join

1 - \frac{x ^{2}}{2} : \frac{2 - x ^{2}}{2}

= \frac{2 - x ^{2}}{2} (x - \frac{x ^{3}}{6})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 - x ^{2} ) ( x - \frac{x ^{3}}{6} )}{2}

Simplify

(2 - x^{2}) (x - \frac{x ^{3}}{6}) : \frac{( 2 - x ^{2} ) ( x \cdot 6 - x ^{3} )}{6}

= \frac{\frac{( 2 - x ^{2} ) ( x \cdot 6 - x ^{3} )}{6}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 - x ^{2} ) ( x \cdot 6 - x ^{3} )}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{( 2 - x ^{2} ) ( x \cdot 6 - x ^{3} )}{12}

= \frac{( 2 - x ^{2} ) ( 6 x - x ^{3} )}{12}

l im x \Rightarrow 0 - (cos (2 x) + x^{2}) cot (3 x)

\frac{5 x ^{2} + 9 x + 3}{x ( x + 1 ) ^{2}}

\frac{8 x ^{\frac{2}{3}}}{( 4 x - 3 ) ^{\frac{2}{3}} ( 4 x + 3 ) ^{\frac{2}{3}}}

(y - 3)^{2} cos (t)

What is (1-((x^2))/2)*(x-((x^3))/6) ?
The solution to (1-((x^2))/2)*(x-((x^3))/6) is ((2-x^2)(6x-x^3))/(12)