What is expand ((2x+3)(x-6))/((x+2)(x-1)) ?

The solution to expand ((2x+3)(x-6))/((x+2)(x-1)) is (2x^2-9x-18)/(x^2+x-2)

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expand ((2x+3)(x-6))/((x+2)(x-1))

expand

\frac{( 2 x + 3 ) ( x - 6 )}{( x + 2 ) ( x - 1 )}

\frac{2 x ^{2} - 9 x - 18}{x ^{2} + x - 2}

Solution steps

\frac{( 2 x + 3 ) ( x - 6 )}{( x + 2 ) ( x - 1 )}

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \frac{( 2 x + 3 ) ( x - 6 )}{x ^{2} + x - 2}

Expand

(2 x + 3) (x - 6) : 2 x^{2} - 9 x - 18

= \frac{2 x ^{2} - 9 x - 18}{x ^{2} + x - 2}

\frac{4}{( x - 3 ) ( x + 1 )}

(\frac{5}{x + 2} + \frac{12}{x ^{2} - 4} + \frac{3}{2 - x}) (x + 2)

\frac{x + 1}{x ( x - 2 )}

(e^{3 x} + 4 e^{- 2 x})^{2}

P (4, - 3) y Q (- 2, 0)

What is expand ((2x+3)(x-6))/((x+2)(x-1)) ?
The solution to expand ((2x+3)(x-6))/((x+2)(x-1)) is (2x^2-9x-18)/(x^2+x-2)