What is expand (4(sin(2pin)-pincos(2pin)))/(n^2) ?

The solution to expand (4(sin(2pin)-pincos(2pin)))/(n^2) is (4sin(2pin)}{n^2}-\frac{4picos(2pin))/n

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expand (4(sin(2pin)-pincos(2pin)))/(n^2)

expand

\frac{4 ( sin ( 2 πn ) - πn cos ( 2 πn ) )}{n ^{2}}

\frac{4 sin ( 2 πn )}{n ^{2}} - \frac{4 π cos ( 2 πn )}{n}

Solution steps

\frac{4 ( sin ( 2 πn ) - πn cos ( 2 πn ) )}{n ^{2}}

Expand

4 (sin (2 πn) - πn cos (2 πn)) : 4 sin (2 πn) - 4 πn cos (2 πn)

= \frac{4 sin ( 2 πn ) - 4 πn cos ( 2 πn )}{n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 sin ( 2 πn ) - 4 πn cos ( 2 πn )}{n ^{2}} = \frac{4 sin ( 2 πn )}{n ^{2}} - \frac{4 πn cos ( 2 πn )}{n ^{2}}

= \frac{4 sin ( 2 πn )}{n ^{2}} - \frac{4 πn cos ( 2 πn )}{n ^{2}}

Cancel

\frac{4 πn cos ( 2 πn )}{n ^{2}} : \frac{4 π cos ( 2 πn )}{n}

= \frac{4 sin ( 2 πn )}{n ^{2}} - \frac{4 π cos ( 2 πn )}{n}

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\frac{d ^{2} y}{d ^{2} x} (x + sin (y) = y + 3)

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What is expand (4(sin(2pin)-pincos(2pin)))/(n^2) ?
The solution to expand (4(sin(2pin)-pincos(2pin)))/(n^2) is (4sin(2pin)}{n^2}-\frac{4picos(2pin))/n