What is expand (4x-28)/(3(x+2)(x-5)) ?

The solution to expand (4x-28)/(3(x+2)(x-5)) is (4x-28)/(3x^2-9x-30)

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expand (4x-28)/(3(x+2)(x-5))

expand

\frac{4 x - 28}{3 ( x + 2 ) ( x - 5 )}

\frac{4 x - 28}{3 x ^{2} - 9 x - 30}

Solution steps

\frac{4 x - 28}{3 ( x + 2 ) ( x - 5 )}

Expand

3 (x + 2) (x - 5) : 3 x^{2} - 9 x - 30

= \frac{4 x - 28}{3 x ^{2} - 9 x - 30}

(x - 2)^{5} (x + 2)^{6} x^{4}

\frac{- 10 + 2 x ^{2}}{x ( 1 + x ^{2} ) ( 4 + x ^{2} )}

(x + y + x - y)^{2}

4 (3 m^{2} - 7 m + 2)^{2}

What is expand (4x-28)/(3(x+2)(x-5)) ?
The solution to expand (4x-28)/(3(x+2)(x-5)) is (4x-28)/(3x^2-9x-30)