What are the solutions to the equation 8z^2-7z-3=0 ?

The solutions to the equation 8z^2-7z-3=0 are z=(7+sqrt(145))/(16),z=(7-sqrt(145))/(16)

Find the zeros of 8z^2-7z-3=0

The zeros of 8z^2-7z-3=0 are z=(7+sqrt(145))/(16),z=(7-sqrt(145))/(16)

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8 z^{2} - 7 z - 3 = 0

z = \frac{7 + 145}{16}, z = \frac{7 - 145}{16}

Solution steps

8 z^{2} - 7 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

(- 7)^{2} - 4 \cdot 8 (- 3) = 145

z_{1, 2} = \frac{- ( - 7 ) \pm 145}{2 \cdot 8}

Separate the solutions

z_{1} = \frac{- ( - 7 ) + 145}{2 \cdot 8}, z_{2} = \frac{- ( - 7 ) - 145}{2 \cdot 8}

z = \frac{- ( - 7 ) + 145}{2 \cdot 8} : \frac{7 + 145}{16}

z = \frac{- ( - 7 ) - 145}{2 \cdot 8} : \frac{7 - 145}{16}

The solutions to the quadratic equation are:

z = \frac{7 + 145}{16}, z = \frac{7 - 145}{16}

9 \cdot 9.8

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2 p^{5} + 10 p^{4} - 48 p^{3}

What are the solutions to the equation 8z^2-7z-3=0 ?
The solutions to the equation 8z^2-7z-3=0 are z=(7+sqrt(145))/(16),z=(7-sqrt(145))/(16)
Find the zeros of 8z^2-7z-3=0
The zeros of 8z^2-7z-3=0 are z=(7+sqrt(145))/(16),z=(7-sqrt(145))/(16)