What is expand dx(x^2+y^2-5=0) ?

The solution to expand dx(x^2+y^2-5=0) is x^2dx+y^2dx-5dx=0

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expand dx(x^2+y^2-5=0)

expand

d x (x^{2} + y^{2} - 5 = 0)

x^{2} d x + y^{2} d x - 5 d x = 0

Solution steps

d x (x^{2} + y^{2} - 5 = 0)

= d x (x^{2} + y^{2} - 5 \cdot 0 =)

Distribute parentheses

= d x x^{2} + d x y^{2} + d x (- 5 = 0)

Apply minus-plus rules

+ (- a) = - a

x^{2} d x + y^{2} d x - 5 d x = 0

(b) (a b - b a)

\frac{x ^{2} + 2 x + 9}{( x ^{2} + 1 ) ( x + 4 )}

lo g_{10} (8) (x^{4})

\frac{2 x - 1}{( x + 2 ) ( x ^{2} + 1 )}

(1 - sin (θ)) (sec (θ) + tan (θ))

What is expand dx(x^2+y^2-5=0) ?
The solution to expand dx(x^2+y^2-5=0) is x^2dx+y^2dx-5dx=0