What is ((-1+sqrt(3)i)^4)/(16) ?

The solution to ((-1+sqrt(3)i)^4)/(16) is -1/2+(sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((-1+sqrt(3)i)^4)/(16)

simplify

\frac{( - 1 + 3 i ) ^{4}}{16}

- \frac{1}{2} + \frac{3}{2} i

Solution steps

\frac{( - 1 + 3 i ) ^{4}}{16}

Expand

(- 1 + 3 i)^{4} : 83 i - 8

= \frac{8 3 i - 8}{16}

Factor out common term

8 : 8 (3 i - 1)

= \frac{8 ( 3 i - 1 )}{16}

Factor the number:

16 = 8 \cdot 2

= \frac{8 ( 3 i - 1 )}{8 \cdot 2}

Cancel the common factor:

8

= \frac{3 i - 1}{2}

Simplify

\frac{3 i - 1}{2} : - \frac{1}{2} + \frac{3}{2} i

= - \frac{1}{2} + \frac{3}{2} i

lo g_{10} (a) r i t hmi c

2 (11 + 7)

\frac{8 x + 6}{( x + 6 ) ( 6 x - 1 )}

(x, y) (x + 3, y - 2)

\frac{2}{( 1 - e ^{(j \cdot (\frac{π}{4} - w))} )}

What is ((-1+sqrt(3)i)^4)/(16) ?
The solution to ((-1+sqrt(3)i)^4)/(16) is -1/2+(sqrt(3))/2 i