What is expand 1/((s+1)(s^2+4s+13)) ?

The solution to expand 1/((s+1)(s^2+4s+13)) is 1/(s^3+5s^2+17s+13)

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expand 1/((s+1)(s^2+4s+13))

expand

\frac{1}{( s + 1 ) ( s ^{2} + 4 s + 13 )}

\frac{1}{s ^{3} + 5 s ^{2} + 17 s + 13}

Solution steps

\frac{1}{( s + 1 ) ( s ^{2} + 4 s + 13 )}

Expand

(s + 1) (s^{2} + 4 s + 13) : s^{3} + 5 s^{2} + 17 s + 13

= \frac{1}{s ^{3} + 5 s ^{2} + 17 s + 13}

x^{2} + y^{2} \cdot (x^{2} + y^{2})

(x + 3 - 2) (x + 3 + 2)

\frac{10 ( s + 4 )}{s ( s + 1 ) ( s + 200 )}

\frac{\partial}{\partial x} ((z) (16 - x^{2} - y^{2}))

\frac{x ( x + 1 )}{5 ( x - 9 )}

What is expand 1/((s+1)(s^2+4s+13)) ?
The solution to expand 1/((s+1)(s^2+4s+13)) is 1/(s^3+5s^2+17s+13)