What are the solutions to the equation -x^2-1=0 ?

The solutions to the equation -x^2-1=0 are x=i,x=-i

Find the zeros of -x^2-1=0

The zeros of -x^2-1=0 are x=i,x=-i

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- x^{2} - 1 = 0

x = i, x = - i

Solution steps

- x^{2} - 1 = 0

Move

1

to the right side

- x^{2} = 1

Divide both sides by

- 1

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

64 x^{8} y^{4} - 1

7^{17} mod 77

\frac{2 x - 5}{4} - 1 = \frac{x + 1}{3}

6 x^{2} + 11 x - 2 \geq 0

\frac{1}{3} (t - 2) + \frac{2}{3} t = 2 t + \frac{4}{3}

What are the solutions to the equation -x^2-1=0 ?
The solutions to the equation -x^2-1=0 are x=i,x=-i
Find the zeros of -x^2-1=0
The zeros of -x^2-1=0 are x=i,x=-i