en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (t+Δt)^2

Solution

expand

(t + Δ t)^{2}

Solution

t^{2} + 2Δ t^{2} + Δ^{2} t^{2}

Solution steps

(t + Δ t)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = t, b = Δ t

= t^{2} + 2 t Δ t + (Δ t)^{2}

Simplify

t^{2} + 2 t Δ t + (Δ t)^{2} : t^{2} + 2Δ t^{2} + Δ^{2} t^{2}

= t^{2} + 2Δ t^{2} + Δ^{2} t^{2}

Popular Examples

expand 12(Ae^{4x}+Be^{-3x})expand

12 (A e^{4 x} + B e^{- 3 x})

expand (3(3x+2)(x+5))/((x-1)(x-3))expand

\frac{3 ( 3 x + 2 ) ( x + 5 )}{( x - 1 ) ( x - 3 )}

expand e^x*(x+1)expand

e^{x} \cdot (x + 1)

expand 1/4 c-3(1/2 c+3=-3/4 c)expand

\frac{1}{4} c - 3 (\frac{1}{2} c + 3 = - \frac{3}{4} c)

expand (x+y+1)^2dx+(x+y-1)^2dy expand

(x + y + 1)^{2} d x + (x + y - 1)^{2} d y

Frequently Asked Questions (FAQ)

What is expand (t+Δt)^2 ?
The solution to expand (t+Δt)^2 is t^2+2Δt^2+Δ^2t^2