What is expand-(2(2x-1))/(3(x^2-x)^{1/3)} ?

The solution to expand-(2(2x-1))/(3(x^2-x)^{1/3)} is -(4x)/(3(x^2-x)^{1/3)}+2/(3(x^2-x)^{1/3)}

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expand-(2(2x-1))/(3(x^2-x)^{1/3)}

expand

- \frac{2 ( 2 x - 1 )}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

- \frac{4 x}{3 ( x ^{2} - x ) ^{\frac{1}{3}}} + \frac{2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

Solution steps

- \frac{2 ( 2 x - 1 )}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

Expand

2 (2 x - 1) : 4 x - 2

= - \frac{4 x - 2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x - 2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}} = - (\frac{4 x}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}) - (- \frac{2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}})

= - (\frac{4 x}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}) - (- \frac{2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{4 x}{3 ( x ^{2} - x ) ^{\frac{1}{3}}} + \frac{2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

(x^{- 1})^{2}

\frac{2 ( 2 x - 3 )}{9 x ^{2} ( x + 1 )}

\frac{( x - 4 ) ( x + 2 )}{( x + 8 ) ( x + 1 )}

(x - i)^{2}

\frac{9 ( - 189 π + 1620 )}{10}

What is expand-(2(2x-1))/(3(x^2-x)^{1/3)} ?
The solution to expand-(2(2x-1))/(3(x^2-x)^{1/3)} is -(4x)/(3(x^2-x)^{1/3)}+2/(3(x^2-x)^{1/3)}