What is expand (2(2x-1))/(3(x^2-x)^{1/3)} ?

The solution to expand (2(2x-1))/(3(x^2-x)^{1/3)} is (4x)/(3(x^2-x)^{1/3)}-2/(3(x^2-x)^{1/3)}

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expand (2(2x-1))/(3(x^2-x)^{1/3)}

expand

\frac{2 ( 2 x - 1 )}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

\frac{4 x}{3 ( x ^{2} - x ) ^{\frac{1}{3}}} - \frac{2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

Solution steps

\frac{2 ( 2 x - 1 )}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

Expand

2 (2 x - 1) : 4 x - 2

= \frac{4 x - 2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x - 2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}} = \frac{4 x}{3 ( x ^{2} - x ) ^{\frac{1}{3}}} - \frac{2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

= \frac{4 x}{3 ( x ^{2} - x ) ^{\frac{1}{3}}} - \frac{2}{3 ( x ^{2} - x ) ^{\frac{1}{3}}}

\frac{x ^{3} + x ^{2} + 1}{x ( x - 1 ) ( x ^{2} + x + 1 ) ( x ^{2} + 1 ) ^{3}}

(t^{2} + e^{t}) \cdot u \cdot (t - 3)

(\frac{x - 6}{5} - \frac{3 x + 1}{7})^{2}

\frac{1}{s ^{2} ( s ^{2} - 2 s + 5 )}

\frac{( s + 2 )}{s ( s ^{2} + 2 s + 2 )}

What is expand (2(2x-1))/(3(x^2-x)^{1/3)} ?
The solution to expand (2(2x-1))/(3(x^2-x)^{1/3)} is (4x)/(3(x^2-x)^{1/3)}-2/(3(x^2-x)^{1/3)}