What is (a+(c-a)/6)(1+x^2) ?

The solution to (a+(c-a)/6)(1+x^2) is ((5a+c)(1+x^2))/6

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simplify (a+(c-a)/6)(1+x^2)

simplify

(a + \frac{c - a}{6}) (1 + x^{2})

\frac{( 5 a + c ) ( 1 + x ^{2} )}{6}

Solution steps

(a + \frac{c - a}{6}) (1 + x^{2})

Join

a + \frac{c - a}{6} : \frac{5 a + c}{6}

= \frac{5 a + c}{6} (1 + x^{2})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 5 a + c ) ( 1 + x ^{2} )}{6}

(\frac{4}{3} - x)^{4}

(x^{2} + y^{2}) (7 x + \frac{2}{3})

\frac{3 x ^{2} + 7 x}{( x - 1 ) ( x ^{2} + 4 x + 5 )}

\frac{2 ( x - 2 )}{x - 1}

(x - 8) (\frac{8}{x - 8} + 9 (100 - x))

What is (a+(c-a)/6)(1+x^2) ?
The solution to (a+(c-a)/6)(1+x^2) is ((5a+c)(1+x^2))/6