What is expand (sin(θ)+3)(sin(θ)-4) ?

The solution to expand (sin(θ)+3)(sin(θ)-4) is sin^2(θ)-sin(θ)-12

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expand (sin(θ)+3)(sin(θ)-4)

expand

(sin (θ) + 3) (sin (θ) - 4)

sin^{2} (θ) - sin (θ) - 12

Solution steps

(sin (θ) + 3) (sin (θ) - 4)

Apply FOIL method

(sin (θ) + 3) (sin (θ) - 4) : sin^{2} (θ) - sin (θ) - 12

= sin^{2} (θ) - sin (θ) - 12

\frac{( 2 x + 5 ) ( 2 x + 1 )}{3 x ( 2 x - 1 )}

(x^{4})^{2}

(\frac{x ^{2}}{2} - \frac{2}{x})^{9}

t^{2} (sin (a t) + e^{a t})

(z - 3 i)^{2}

What is expand (sin(θ)+3)(sin(θ)-4) ?
The solution to expand (sin(θ)+3)(sin(θ)-4) is sin^2(θ)-sin(θ)-12