What is expand (x^2+1)ln(x+1) ?

The solution to expand (x^2+1)ln(x+1) is x^2ln(x+1)+ln(x+1)

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expand (x^2+1)ln(x+1)

expand

(x^{2} + 1) ln (x + 1)

x^{2} ln (x + 1) + ln (x + 1)

Solution steps

(x^{2} + 1) ln (x + 1)

= ln (x + 1) (x^{2} + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = ln (x + 1), b = x^{2}, c = 1

= ln (x + 1) x^{2} + ln (x + 1) \cdot 1

= x^{2} ln (x + 1) + 1 \cdot ln (x + 1)

Multiply:

1 \cdot ln (x + 1) = ln (x + 1)

= x^{2} ln (x + 1) + ln (x + 1)

(- 2, - 1, 4) l e f t (4, 8, 4)

(120 \cdot cos (θ) - 120) \cdot (0.3 \cdot sin (θ))

(5 e^{2 t} - 3)^{2}

\frac{\partial}{\partial x} ((z) (x^{2} ln (y) - z))

(a - 1, b) (a + 1, b + 1)

What is expand (x^2+1)ln(x+1) ?
The solution to expand (x^2+1)ln(x+1) is x^2ln(x+1)+ln(x+1)