What is (1-e^{ix})^2 ?

The solution to (1-e^{ix})^2 is (1-cos(x)-isin(x))^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (1-e^{ix})^2

simplify

(1 - e^{i x})^{2}

(1 - cos (x) - i sin (x))^{2}

Solution steps

(1 - e^{i x})^{2}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= (1 - (cos (x) + i sin (x)))^{2}

Expand

1 - (cos (x) + sin (x) i) : 1 - cos (x) - sin (x) i

= (1 - cos (x) - i sin (x))^{2}

(x + 5 - 3) \cdot (x + 5 + 3)

\frac{e ^{s}}{s ( s ^{2} + 1 )}

3 (x + y)^{2} (1 + \frac{d y}{d x})

(\frac{( e ^{x} + e ^{- x} )}{2})^{4}

P (6, 2, - 5) Q (0, - 5, - 3)