What is expand x^{1/3}(4x-4) ?

The solution to expand x^{1/3}(4x-4) is 4x^{4/3}-x^{1/3}*4

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expand x^{1/3}(4x-4)

expand

x^{\frac{1}{3}} (4 x - 4)

4 x^{\frac{4}{3}} - x^{\frac{1}{3}} \cdot 4

Solution steps

x^{\frac{1}{3}} (4 x - 4)

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{1}{3}} (4 x - 4) = x^{\frac{1}{3}} \cdot 4 x - x^{\frac{1}{3}} \cdot 4

= x^{\frac{1}{3}} \cdot 4 x - x^{\frac{1}{3}} \cdot 4

Simplify

x^{\frac{1}{3}} \cdot 4 x : 4 x^{\frac{4}{3}}

= 4 x^{\frac{4}{3}} - x^{\frac{1}{3}} \cdot 4

\frac{27 + 3 s ^{3} + 2 s ^{2}}{s ^{2} ( s ^{2} + 9 )}

\frac{x ( x ^{2} + 1 )}{( x + 1 ) ( x - 1 )}

(L^{\frac{1}{3}} + K^{\frac{1}{3}})^{3}

(1 + cos (x))^{3}

What is expand x^{1/3}(4x-4) ?
The solution to expand x^{1/3}(4x-4) is 4x^{4/3}-x^{1/3}*4