What is expand-((s^3+s^2+6s-2)/(s(s+3)(s-1))) ?

The solution to expand-((s^3+s^2+6s-2)/(s(s+3)(s-1))) is -(s^3+s^2+6s-2)/(s^3+2s^2-3s)

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expand-((s^3+s^2+6s-2)/(s(s+3)(s-1)))

expand

- (\frac{s ^{3} + s ^{2} + 6 s - 2}{s ( s + 3 ) ( s - 1 )})

- \frac{s ^{3} + s ^{2} + 6 s - 2}{s ^{3} + 2 s ^{2} - 3 s}

Solution steps

- (\frac{s ^{3} + s ^{2} + 6 s - 2}{s ( s + 3 ) ( s - 1 )})

Remove parentheses:

(a) = a

= - \frac{s ^{3} + s ^{2} + 6 s - 2}{s ( s + 3 ) ( s - 1 )}

Expand

s (s + 3) (s - 1) : s^{3} + 2 s^{2} - 3 s

= - \frac{s ^{3} + s ^{2} + 6 s - 2}{s ^{3} + 2 s ^{2} - 3 s}

\frac{x ( 2 - x ) ^{3}}{3}

(t cos (u), t sin (u), u) \cdot (sin (u), - cos (u), t)

(2 a + b) (2 a - b)

(3 x + \frac{2}{x})^{8}

(3 - 4 i) (3 + 4 i)

What is expand-((s^3+s^2+6s-2)/(s(s+3)(s-1))) ?
The solution to expand-((s^3+s^2+6s-2)/(s(s+3)(s-1))) is -(s^3+s^2+6s-2)/(s^3+2s^2-3s)