What is expand ((x-1)(3x+2))/3 ?

The solution to expand ((x-1)(3x+2))/3 is x^2-x/3-2/3

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expand ((x-1)(3x+2))/3

expand

\frac{( x - 1 ) ( 3 x + 2 )}{3}

x^{2} - \frac{x}{3} - \frac{2}{3}

Solution steps

\frac{( x - 1 ) ( 3 x + 2 )}{3}

Expand

(x - 1) (3 x + 2) : 3 x^{2} - x - 2

= \frac{3 x ^{2} - x - 2}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} - x - 2}{3} = \frac{3 x ^{2}}{3} - \frac{x}{3} - \frac{2}{3}

= \frac{3 x ^{2}}{3} - \frac{x}{3} - \frac{2}{3}

Divide the numbers:

\frac{3}{3} = 1

= x^{2} - \frac{x}{3} - \frac{2}{3}

\frac{2 tan ( x )}{x ( 1 - tan ^{2} ( x ) )}

(3 x^{2} - \frac{5}{3 x ^{3}}) (3 x^{2} + \frac{5}{3 x ^{3}})

580 (e^{- \frac{x}{90}} - \frac{e ^{- \frac{x}{90}} x}{90})

a (- 1, - 3)

\frac{10}{s ( s + 3 )}

What is expand ((x-1)(3x+2))/3 ?
The solution to expand ((x-1)(3x+2))/3 is x^2-x/3-2/3