What is expand ((x+5)(2x-7))/((x+1)^2) ?

The solution to expand ((x+5)(2x-7))/((x+1)^2) is (2x^2+3x-35)/(x^2+2x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x+5)(2x-7))/((x+1)^2)

expand

\frac{( x + 5 ) ( 2 x - 7 )}{( x + 1 ) ^{2}}

\frac{2 x ^{2} + 3 x - 35}{x ^{2} + 2 x + 1}

Solution steps

\frac{( x + 5 ) ( 2 x - 7 )}{( x + 1 ) ^{2}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{( x + 5 ) ( 2 x - 7 )}{x ^{2} + 2 x + 1}

Expand

(x + 5) (2 x - 7) : 2 x^{2} + 3 x - 35

= \frac{2 x ^{2} + 3 x - 35}{x ^{2} + 2 x + 1}

A (- 2, - 3) B (5, 1)

(- 5 + 12 i)^{4}

(10 + \frac{50}{ln ( 2 x + 5 )}) (x)

(- 8 sin (x) + 3 cos (x)) (- 8 cos (x) - 3 sin (x))

(3 + 1) (2 - 1)

What is expand ((x+5)(2x-7))/((x+1)^2) ?
The solution to expand ((x+5)(2x-7))/((x+1)^2) is (2x^2+3x-35)/(x^2+2x+1)