What is 0.004*(n-1)^2-3/n ?

The solution to 0.004*(n-1)^2-3/n is (0.004n^3-0.008n^2+0.004n-3)/n

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simplify 0.004*(n-1)^2-3/n

simplify

0.004 \cdot (n - 1)^{2} - \frac{3}{n}

\frac{0.004 n ^{3} - 0.008 n ^{2} + 0.004 n - 3}{n}

Solution steps

0.004 (n - 1)^{2} - \frac{3}{n}

Apply the fraction rule:

a - \frac{b}{c} = \frac{a c - b}{c}

= \frac{0.004 ( n - 1 ) ^{2} n - 3}{n}

Simplify

0.004 (n - 1)^{2} n - 3 : 0.004 n^{3} - 0.008 n^{2} + 0.004 n - 3

= \frac{0.004 n ^{3} - 0.008 n ^{2} + 0.004 n - 3}{n}

lo g_{10} (3 x)

\frac{3}{n ( n + 1 )}

\frac{s ^{2} + 6 s + 9}{( s + 4 ) ( s - 2 ) ( s - 1 )}

\frac{( ( A \cdot x ) - 1 ) ^{2}}{( ( B \cdot x ) - 1 ) ^{2} \cdot ( ( C \cdot x ) - 1 ) ^{2}}

\frac{tan ( t )}{( t - 3 ) ( t - 5 )}

What is 0.004*(n-1)^2-3/n ?
The solution to 0.004*(n-1)^2-3/n is (0.004n^3-0.008n^2+0.004n-3)/n