What is expand ((x^2-4)(x-3))/(x+1) ?

The solution to expand ((x^2-4)(x-3))/(x+1) is (x^3-3x^2-4x+12)/(x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x^2-4)(x-3))/(x+1)

expand

\frac{( x ^{2} - 4 ) ( x - 3 )}{x + 1}

\frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x + 1}

Solution steps

\frac{( x ^{2} - 4 ) ( x - 3 )}{x + 1}

Expand

(x^{2} - 4) (x - 3) : x^{3} - 3 x^{2} - 4 x + 12

= \frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x + 1}

(5 + 3) (6 - 4)

(f \circ g) (4 x + 4) (x^{2})

\frac{6}{( x - 1 ) ( x + 1 )}

(x + 2 x)^{2}

\frac{( 2 x + v ^{2} x - 1 )}{x ^{2} ( v + 1 )}

What is expand ((x^2-4)(x-3))/(x+1) ?
The solution to expand ((x^2-4)(x-3))/(x+1) is (x^3-3x^2-4x+12)/(x+1)