What is expand (x-1)*e^{x+1} ?

The solution to expand (x-1)*e^{x+1} is e^{x+1}x-e^{x+1}

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expand (x-1)*e^{x+1}

expand

(x - 1) \cdot e^{x + 1}

e^{x + 1} x - e^{x + 1}

Solution steps

(x - 1) e^{x + 1}

= e^{x + 1} (x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x + 1}, b = x, c = 1

= e^{x + 1} x - e^{x + 1} \cdot 1

= e^{x + 1} x - 1 \cdot e^{x + 1}

Multiply:

1 \cdot e^{x + 1} = e^{x + 1}

= e^{x + 1} x - e^{x + 1}

e^{3 x} (1 - 3 x)

ln (\frac{x ^{4}}{y ^{5}})

(2 - i 3) (2 - i 3)

(a x^{2} + b x + c) (d x^{2} + e x + f)

(1 - sin (x)) (1 + csc (x)) sin (x)

What is expand (x-1)*e^{x+1} ?
The solution to expand (x-1)*e^{x+1} is e^{x+1}x-e^{x+1}