What is expand 3/((s^2+4)(s^2+9)) ?

The solution to expand 3/((s^2+4)(s^2+9)) is 3/(s^4+13s^2+36)

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expand 3/((s^2+4)(s^2+9))

expand

\frac{3}{( s ^{2} + 4 ) ( s ^{2} + 9 )}

\frac{3}{s ^{4} + 13 s ^{2} + 36}

Solution steps

\frac{3}{( s ^{2} + 4 ) ( s ^{2} + 9 )}

Expand

(s^{2} + 4) (s^{2} + 9) : s^{4} + 13 s^{2} + 36

= \frac{3}{s ^{4} + 13 s ^{2} + 36}

\frac{3}{2} + \frac{1}{3} (x - \frac{5}{4}) - \frac{1}{27} (x - \frac{5}{4})^{2}

- 1 (2 x + y = 7)

\frac{2 a ^{2}}{s ( s ^{2} - 4 a ^{2} )}

(3 + a) (3 - a)

(x + 5) (x + 10) (x - 10)

What is expand 3/((s^2+4)(s^2+9)) ?
The solution to expand 3/((s^2+4)(s^2+9)) is 3/(s^4+13s^2+36)