What is expand (8sin(x)+8cos(x))^2 ?

The solution to expand (8sin(x)+8cos(x))^2 is 64sin(2x)+64

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expand (8sin(x)+8cos(x))^2

expand

(8 sin (x) + 8 cos (x))^{2}

64 sin (2 x) + 64

Solution steps

(8 sin (x) + 8 cos (x))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(8 sin (x) + 8 cos (x))^{2} = (8 sin (x))^{2} + 2 \cdot 8 sin (x) \cdot 8 cos (x) + (8 cos (x))^{2}

= (8 sin (x))^{2} + 2 \cdot 8 sin (x) \cdot 8 cos (x) + (8 cos (x))^{2}

Simplify

(8 sin (x))^{2} + 2 \cdot 8 sin (x) \cdot 8 cos (x) + (8 cos (x))^{2} : 64 (sin (2 x) + 1)

= 64 (sin (2 x) + 1)

Apply the distributive law:

a (b + c) = ab + a c

64 (sin (2 x) + 1) = 64 sin (2 x) + 64 \cdot 1

= 64 sin (2 x) + 64 \cdot 1

Multiply the numbers:

64 \cdot 1 = 64

= 64 sin (2 x) + 64

\frac{d}{d t} ((x) (arctan (\frac{3}{x}) + arctan (\frac{9}{x})))

y^{\frac{1}{2}} (y^{\frac{3}{2}} - y^{\frac{3}{5}})

B (1, - 3)

lo g_{10} (b) (7 x \cdot 2 y)

\frac{1}{( n + k ) ( n + k + 1 )}

What is expand (8sin(x)+8cos(x))^2 ?
The solution to expand (8sin(x)+8cos(x))^2 is 64sin(2x)+64