What is expand (3x^2+18x+27)(x+3)^{1/5} ?

The solution to expand (3x^2+18x+27)(x+3)^{1/5} is (x+3)^{1/5}*3x^2+(x+3)^{1/5}*18x+(x+3)^{1/5}*27

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expand (3x^2+18x+27)(x+3)^{1/5}

expand

(3 x^{2} + 18 x + 27) (x + 3)^{\frac{1}{5}}

(x + 3)^{\frac{1}{5}} \cdot 3 x^{2} + (x + 3)^{\frac{1}{5}} \cdot 18 x + (x + 3)^{\frac{1}{5}} \cdot 27

Solution steps

(3 x^{2} + 18 x + 27) (x + 3)^{\frac{1}{5}}

= (x + 3)^{\frac{1}{5}} (3 x^{2} + 18 x + 27)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

(x + 3)^{\frac{1}{5}} (3 x^{2} + 18 x + 27) = (x + 3)^{\frac{1}{5}} \cdot 3 x^{2} + (x + 3)^{\frac{1}{5}} \cdot 18 x + (x + 3)^{\frac{1}{5}} \cdot 27

= (x + 3)^{\frac{1}{5}} \cdot 3 x^{2} + (x + 3)^{\frac{1}{5}} \cdot 18 x + (x + 3)^{\frac{1}{5}} \cdot 27

\frac{2}{s ( s + 1 ) ( s + 4 )}

(P (x) + q (x)) l e f t (q (x) - R (x))

\frac{6 ( x - 8 )}{7 ( 2 x - 5 )}

(z^{2} + i)^{2}

- \frac{6 ( - 3 x ^{2} + 5 )}{( 3 x ^{2} + 5 ) ^{2}}

What is expand (3x^2+18x+27)(x+3)^{1/5} ?
The solution to expand (3x^2+18x+27)(x+3)^{1/5} is (x+3)^{1/5}*3x^2+(x+3)^{1/5}*18x+(x+3)^{1/5}*27