What is expand ((x-3)(x+4))/(x^2-1) ?

The solution to expand ((x-3)(x+4))/(x^2-1) is (x^2+x-12)/(x^2-1)

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expand ((x-3)(x+4))/(x^2-1)

expand

\frac{( x - 3 ) ( x + 4 )}{x ^{2} - 1}

\frac{x ^{2} + x - 12}{x ^{2} - 1}

Solution steps

\frac{( x - 3 ) ( x + 4 )}{x ^{2} - 1}

Expand

(x - 3) (x + 4) : x^{2} + x - 12

= \frac{x ^{2} + x - 12}{x ^{2} - 1}

\frac{4}{x ( x ^{2} + 2 )}

(1 - b) (1 + b)

(x^{3} + 89 - x^{3} + 9)^{2}

cos (\frac{( 3 n - 2 ) π}{3})

2 (x + 1) x + 1

What is expand ((x-3)(x+4))/(x^2-1) ?
The solution to expand ((x-3)(x+4))/(x^2-1) is (x^2+x-12)/(x^2-1)