What is expand sin(t)-sin(t)(u)(t-2pi) ?

The solution to expand sin(t)-sin(t)(u)(t-2pi) is sin(t)-tusin(t)+2piusin(t)

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expand sin(t)-sin(t)(u)(t-2pi)

expand

sin (t) - sin (t) (u) (t - 2 π)

sin (t) - t u sin (t) + 2 π u sin (t)

Solution steps

sin (t) - sin (t) (u) (t - 2 π)

= sin (t) - (u) sin (t) (t - 2 π)

Expand

- sin (t) (u) (t - 2 π) : - t u sin (t) + 2 π u sin (t)

= sin (t) - t u sin (t) + 2 π u sin (t)

2 cos (2) (x - \frac{π}{3}) - 1

\frac{e ^{x} + x ^{2} e ^{x} - 2 x e ^{x}}{( 1 + x ^{2} ) ^{2}}

(sin (5 x) - cos (5 x))^{5}

\frac{1}{x ( x + 5 )}

\frac{- a ( b - 2 a ) + 3 c ( - b - 2 a )}{a ( b - 2 a ) + 3 c ( b - 2 a )}

What is expand sin(t)-sin(t)(u)(t-2pi) ?
The solution to expand sin(t)-sin(t)(u)(t-2pi) is sin(t)-tusin(t)+2piusin(t)