What is expand-1/((s^2+1)(s^2+2s+3)) ?

The solution to expand-1/((s^2+1)(s^2+2s+3)) is -1/(s^4+2s^3+4s^2+2s+3)

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expand-1/((s^2+1)(s^2+2s+3))

expand

- \frac{1}{( s ^{2} + 1 ) ( s ^{2} + 2 s + 3 )}

- \frac{1}{s ^{4} + 2 s ^{3} + 4 s ^{2} + 2 s + 3}

Solution steps

- \frac{1}{( s ^{2} + 1 ) ( s ^{2} + 2 s + 3 )}

Expand

(s^{2} + 1) (s^{2} + 2 s + 3) : s^{4} + 2 s^{3} + 4 s^{2} + 2 s + 3

= - \frac{1}{s ^{4} + 2 s ^{3} + 4 s ^{2} + 2 s + 3}

\frac{5 ( 5 - 7 )}{3}

(5 cos (x) - 5 cos (5 x))^{2}

(3 + 6) (6 + 5)

\frac{( x ^{2} ( e ^{x} - 1 ) )}{sin ( x ) - x}

(A + C) (A D + A D^{^{'}}) + A C + C

What is expand-1/((s^2+1)(s^2+2s+3)) ?
The solution to expand-1/((s^2+1)(s^2+2s+3)) is -1/(s^4+2s^3+4s^2+2s+3)