What are the solutions to the equation 2(x-1)^2+4=0 ?

The solutions to the equation 2(x-1)^2+4=0 are x=sqrt(2)i+1,x=-sqrt(2)i+1

Find the zeros of 2(x-1)^2+4=0

The zeros of 2(x-1)^2+4=0 are x=sqrt(2)i+1,x=-sqrt(2)i+1

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2 (x - 1)^{2} + 4 = 0

x = 2 i + 1, x = - 2 i + 1

Solution steps

2 (x - 1)^{2} + 4 = 0

Move

4

to the right side

2 (x - 1)^{2} = - 4

Divide both sides by

2

(x - 1)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - 2 : x = 2 i + 1

Solve

x - 1 = - - 2 : x = - 2 i + 1

The solutions to the quadratic equation are:

x = 2 i + 1, x = - 2 i + 1

8 y^{2} (9 x^{3} y)

49 x^{- \frac{9}{2}} + 14 x^{- \frac{7}{2}} + x^{- \frac{5}{2}}

10 \cdot 6

22 \cdot 2 x + 33 \cdot 2

8^{\frac{5}{2}}

What are the solutions to the equation 2(x-1)^2+4=0 ?
The solutions to the equation 2(x-1)^2+4=0 are x=sqrt(2)i+1,x=-sqrt(2)i+1
Find the zeros of 2(x-1)^2+4=0
The zeros of 2(x-1)^2+4=0 are x=sqrt(2)i+1,x=-sqrt(2)i+1