What is expand x^{1/3}*(x-2)^2 ?

The solution to expand x^{1/3}*(x-2)^2 is x^{7/3}-4x^{4/3}+x^{1/3}*4

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expand x^{1/3}*(x-2)^2

expand

x^{\frac{1}{3}} \cdot (x - 2)^{2}

x^{\frac{7}{3}} - 4 x^{\frac{4}{3}} + x^{\frac{1}{3}} \cdot 4

Solution steps

x^{\frac{1}{3}} (x - 2)^{2}

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

= x^{\frac{1}{3}} (x^{2} - 4 x + 4)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

x^{\frac{1}{3}} (x^{2} - 4 x + 4) = x^{\frac{1}{3}} x^{2} + x^{\frac{1}{3}} (- 4 x) + x^{\frac{1}{3}} \cdot 4

= x^{\frac{1}{3}} x^{2} + x^{\frac{1}{3}} (- 4 x) + x^{\frac{1}{3}} \cdot 4

x^{\frac{1}{3}} x^{2} = x^{\frac{7}{3}}

x^{\frac{1}{3}} (- 4 x) = - 4 x^{\frac{4}{3}}

= x^{\frac{7}{3}} - 4 x^{\frac{4}{3}} + x^{\frac{1}{3}} \cdot 4

(x - y) d x + y^{2} d y

\frac{csc ( a ) ( tan ( a ) - sin ( a ) )}{1 - sec ( a )}

\frac{x ( x + 4 )}{2}

(35 - 2) (4 + 7)

11 (10 + 7)

What is expand x^{1/3}*(x-2)^2 ?
The solution to expand x^{1/3}*(x-2)^2 is x^{7/3}-4x^{4/3}+x^{1/3}*4