What is expand (x^2-x+7)/(6(x+1)(x^2-x+1)) ?

The solution to expand (x^2-x+7)/(6(x+1)(x^2-x+1)) is (x^2-x+7)/(6x^3+6)

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expand (x^2-x+7)/(6(x+1)(x^2-x+1))

expand

\frac{x ^{2} - x + 7}{6 ( x + 1 ) ( x ^{2} - x + 1 )}

\frac{x ^{2} - x + 7}{6 x ^{3} + 6}

Solution steps

\frac{x ^{2} - x + 7}{6 ( x + 1 ) ( x ^{2} - x + 1 )}

Expand

6 (x + 1) (x^{2} - x + 1) : 6 x^{3} + 6

= \frac{x ^{2} - x + 7}{6 x ^{3} + 6}

(5 x y + 6) (5 x y - 6)

\frac{( a + i ) ^{5}}{( 1 - i ) ^{3}}

3 (3 x^{2} + 2 x - 5)^{2}

\frac{( 1 - 2 y ) ^{2}}{2}

11 (10 + 3)

What is expand (x^2-x+7)/(6(x+1)(x^2-x+1)) ?
The solution to expand (x^2-x+7)/(6(x+1)(x^2-x+1)) is (x^2-x+7)/(6x^3+6)