What is expand (x+2)/(2-x-12)+(x-1)/(2+2x) ?

The solution to expand (x+2)/(2-x-12)+(x-1)/(2+2x) is (x^2-3x+14)/(-2x^2-22x-20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+2)/(2-x-12)+(x-1)/(2+2x)

expand

\frac{x + 2}{2 - x - 12} + \frac{x - 1}{2 + 2 x}

\frac{x ^{2} - 3 x + 14}{- 2 x ^{2} - 22 x - 20}

Solution steps

\frac{x + 2}{2 - x - 12} + \frac{x - 1}{2 + 2 x}

2 - x - 12 = - x - 10

= \frac{x + 2}{- x - 10} + \frac{x - 1}{2 x + 2}

Factor

2 x + 2 : 2 (x + 1)

= \frac{x + 2}{- x - 10} + \frac{x - 1}{2 ( x + 1 )}

Least Common Multiplier of

- x - 10, 2 (x + 1) : 2 (x + 1) (- x - 10)

Adjust Fractions based on the LCM

= \frac{( x + 2 ) \cdot 2 ( x + 1 )}{( - x - 10 ) \cdot 2 ( x + 1 )} + \frac{( x - 1 ) ( - x - 10 )}{2 ( x + 1 ) ( - x - 10 )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( x + 2 ) \cdot 2 ( x + 1 ) + ( x - 1 ) ( - x - 10 )}{2 ( x + 1 ) ( - x - 10 )}

Expand

2 (x + 1) (- x - 10) : - 2 x^{2} - 22 x - 20

= \frac{2 ( x + 2 ) ( x + 1 ) + ( x - 1 ) ( - x - 10 )}{- 2 x ^{2} - 22 x - 20}

Expand

(x + 2) \cdot 2 (x + 1) + (x - 1) (- x - 10) : x^{2} - 3 x + 14

= \frac{x ^{2} - 3 x + 14}{- 2 x ^{2} - 22 x - 20}

t^{2} e^{4 t^{5}} (3 - 20 t^{5} - 40 t^{2})

8 (sin (2 x) - cos (2 x))

l im x \Rightarrow - 1 (x^{3} - 2 x^{2} - 5 x - 1)

11 (10 + 2)

π (1 + \frac{3}{5})

What is expand (x+2)/(2-x-12)+(x-1)/(2+2x) ?
The solution to expand (x+2)/(2-x-12)+(x-1)/(2+2x) is (x^2-3x+14)/(-2x^2-22x-20)